Abu Dhabi: Mumbai Indians are back on the road to victory in the IPL 2020 season with a 48-run win over Kings XI. That was the 2nd win in the Tourney.
Chasing a huge 192-run target, Mumbai Indians managed to score 143 runs for the loss of 8 wickets in their 20 overs.
Chasing 192 for victory, Kings XI Punjab gave captain KL Rahul and Mayank Agarwal a splendid start. After a stormy batting start, Punjab scored 37 runs in the first 4 overs.
Bumrah’s first success for Mumbai was the clean-bowling of Mayank with explosive batting. Krishnan Pandya shook off Karun Nair’s stunner as he stroked his way through the Mayank Pavilion, scoring 25 off 18 balls.
Rohit Sharma sent Chahar to a bowling attack when Punjab scored 60 in the eighth over, while Rahul, who scored 17 off 19 balls, was let down by Chahar’s first ball. With this, Mumbai managed to cut the pace of the Punjab team.
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Pressurized to score 100 runs in the final 50 balls, Punjab’s players got into a furious game, with James Pattinson succeeding in getting the Poran wicket backed up by a hard-hitting team. He hit 44 off 27 balls with three fours and a six. Chaher bowled 11 wickets and bowled Maxwell’s wicket. Then Nisham (7 runs) returned to the Bumrah Pavilion just as fast. After that, the Mumbai bowlers were able to easily tie down the low-order Punjab batsmen. Finally, Kings XI Punjab lost by 143 runs with 8 wickets.
Earlier, Mumbai Indians skipper Rohit Sharma, who had lost a toss, hit a half-century and hit a massive 191 in 20 overs with the help of Hardik Pandya and Pollard’s explosive batting. Mumbai were bowled out for 104 in the final 6 overs, taking the wickets of the Punjab team well. Mumbai skipper Rohit Sharma hit 70 off 45 balls with 8 fours and three sixes while Hardik made 30 off 11 balls and Pollard 47. Bolt and Karnal Pandya took two wickets each for Mumbai’s Chahar, Bumrah and Pattinson.